Saturday 21 January 2017

FINANCE CALCULATION - An Australian Manufacturing Company Sanitary Product.

An Australian manufacturing company which is a market leader in the sanitary product sector
in the Australasian market with operating headquarters in Sydney is keen to develop new
products so that company can expand into Australian and Asian markets. Research and
Development (R&D) department of the company has prepared a proposal to work on new
product line of fragrance.

Assume you work as an Analyst for this company and you have been asked to study the
market for fragrances. You have been asked to study the characteristics of currently available
fragrances so the company will be in a better position to price its proposed new product. You
have collected data for 95 products on the market. The data is on an excel file named
“FRAGRANCE”.

First Column: PRICE (that is Price of the product in Australian dollars for 100 ml of a
fragrance).
Second Column: GENDER (1 for Female product and 2 for Male product).
Third Column: TYPE (Type of fragrance: 1 for perfume and 2 for cologne).
Forth Column: MADE (the country in which the fragrance is produced: 1 made in France, 2
made in USA, 3 made in other countries).
Fifth Column: INTEN (Intensity or strength of the product: 1 for strong, 2 for medium and 3
for mild).

See next pages for more information. Questions:
Part 1) Provide a description of the data (for all the 95 products together) and show what
Mean, Standard Deviation, Coefficient of Variation mean in this context.

Part 2) Calculate the Mean, Median, Mode, Standard Deviation, Coefficient of Variation,
95% confidence interval for means for:
o Prices for gender - male and female.
o Prices for fragrance - perfume and cologne.
o Prices for intensity - strong, medium and mild.
o Prices for different countries – France, USA and other.
What conclusions can you draw from these analyses? Also comment on the shape of
distributions.

Part 3) You are also required to answer the following questions (For one-sided tests, use the
question of interest as the alternative hypothesis):

1. Determine if average prices for female products exceed average prices for male
products.
2. Determine if there is evidence to suggest that the variance of prices for male products
is equal to those of female products.
3. Determine if average prices for perfume exceeds the average price of cologne.
4. Determine if there is evidence to suggest that the variance of prices for perfume and
cologne are equals.
5. Determine if there is a difference in the prices for intensity.
6. Determine if there is a difference for the prices for different countries.

Give conclusions for each of the analysis plus an overall conclusion which combine all of the
above (parts 1 and 2). Be clear in the conclusion that you draw from your analysis, and
provide some useful suggestions to the company’s manager.

Notes:
v You must follow the hypothesis testing steps to test the above hypotheses. v You must clearly specify all hypotheses and the chosen test procedures.
v Use 0.05 level of significance in your analyses and assume that we have normal
distributions and also “equal variances” of populations.
v Each part requires an output from any statistical computer package (Excel, SPSS, R etc.).
The statistical output must be provided.
v Use and interpret appropriate output from statistical computer packages such as
SPSS/Minitab/Excel/PHStat to conduct hypothesis testing.
v Prepare and produce a business report based on the information provided in the
“Presentation of the assignment”.
v You report can be maximum 3000 words, penalties will be applied if the report is longer
than this.
v Submit the business report as indicated in the “Presentation of the assignment” BEFORE
4pm, 17 April 2014 at the Business Central.
v No assignment will be accepted after 4pm, 17 April 2014.
v Take your assignment to the Business Central to be scanned and submitted
v Please ensure that you have signed the plagiarism declaration before submitting your
assignment for scanning at Business Central.

Executive summary

In this business report the analyst analyze the market about the fragrances. To analyze the market the analyst have taken different kind of variable such as the price of the product, type of the fragrance, the effective gender, the country where the product made and the intensity and the strength of the product.
The analyst use different kind of statistical tools to analyze the market of fragrances. The important statistical tools are mean, median, mode, standard deviation and correlation coefficient.
 As per the analysis, the analyzer observes that the value of mean of price is 29 and the value of median of price of the fragrance is 124. The value of the mode of the product is 69 and the value of the standard deviation is 79.64. 
  

IMPORTANT:

It is compulsory for all students to submit their assignments (only final version) into
the Turnitin system BEFORE submitting the hard copy to the Business Central. Then
an 'originality report' will automatically be sent to the Lecturer (Dr Amir Arjomandi).
Otherwise your assignment will not be marked and therefore you will be awarded a 0
for this assessment task.
• You must submit your assignment to Turnitin before the due date (4pm, 15 April
2014). No assignment will be accepted by Turnitin after 4pm, 15 April 2014.
• The first time a UOW student uses the Turnitin system, they must register using a
functioning UOW email address as their user name and adhere to the following
guidelines:
1. Use one sign in name only
2. Use one document name only for each assignment that includes your UOW student
number 3. Any resubmissions must use the same document name as the original submission
4. References must be included in your Turnitin submission
5. Do not include the assignment topic question at the beginning of your submission.

• Failure to comply with these requirements may result in penalties being applied.

-------------------------------------------------------------

Introduction

An Australian manufacturing company which is a market leader in the sanitary sector in the Australian market with operating headquarters in the Sydney which is keen to develop new products so that company can expand into the Australian and Asian markets. Research and development of this company is going to prepare a proposal to work a new product line in the fragrance. In this project the analyst study the market for fragrance. In this project, the analyst has collected data for 95 products on the market. The analyst has to study the characteristics of the currently available fragrance so the company will be in a better position to price its proposed new product.
The terms of mean median mode and the range that describes properties of the statistical distribution. In the method of statistics, a distribution is one set of possible values which represent defined the events (Atkinson, 2008). Random variable can be expressed as a variable. There are two major type of statistical distribution. The effective type has a discrete random variable. It express hat every term is precise and isolated numerical value (Dimarco, 2008). One of the distributions of discrete random variables is that a set of result for the test taken by the class. Another major type of distribution is a continuous random variable (Comaniciu and Meer, 2002). In that situation, a term has to acquire any within an unbroken interval. This is one of the functions which can be used by a computer in an attempt which forecast the path of a weather system (Lee et al. 2011).       

Mean

One of the most common expressions for the mean of statistical distribution with the discrete random variable is the mathematical average of every term. When the analyst calculates the mean then they have to add the values of all the terms and they have to divide the number of terms (Evanovich, 2007). This method can be called the arithmetic mean. On the other hand, there are other expressions for the mean that a finite set of terms but in mathematics these form are rarely used in the statistical calculation (Comaniciu et al. 2000). The proper mean of the statistical distribution with a following random variables and this can also called the expected value that can be obtained by the integrating the product of the variable with its probability as defined by the effective distribution. The value of mean can be representing by the lower case Greek letter mu (Hughes and Jagannathan, 2009).

Median

Median is another method of dispersion with the discrete random variables which depends on whether the number of the term as per the distribution. When the number of term is odd, then the median is the value of the term in the middle (American Mathematical Society, 2014). When the term of this variable is even then the median is the average of the two terms in the middle which that the numbers of terms have the value greater than or equal to as it is the same as the number of term has the value less than or equal to it (Lenn and Stefano, 2012). On the other hand, the median of the distribution as a continuous random variables is one of the value m such that the probability is at least 50 per cent that a random chosen point on the function that will be less than or equal to the m and on the other aspect the probability is at least ½ that of the random chosen in the point on the function that will be greater than or equal to the m (Arxiv.org, 2014).

Mode

Mode is another aspect of dispersion. As per the mode it is common for a distribution with the discrete random variable that has to be more than one mode, in this case there are not many terms (Fagam et al. 2008). This kind of incident happens at the time when two or more terms occur with the equal frequency. A distribution of the two modes can be known as bimodal. On the other hand, a distribution of three modes can be called as tri modal (Schwarz and Yenmez, 2009). The mode of the distribution as per the continuous random variables is the maximum value of the function (Math.berkeley.edu, 2014). There may more than one mode with discrete distribution.         

Standard deviation

Standard deviation is the measure of dispersion of the set of data for the mean. When the data is more spread the there is a chance of higher deviation. This method is calculated as the square root of the variance (Weissman, 2007). As per the part in finance, standard deviations have to be applied to the annual rate of return of an investment which measures the volatility of the investment (Pagel and Hudetz, 2011). The standard deviation can be known as the historical volatility and which is used by the investors as per the gauge for the amount of expected volatility. When the analyst have to look at the peoples typical daily consumption then number of people typical consumption have to turn out to be normally distributed. The consumption will be close to the mean. The x axis is the value of question which calories consumed, dollars earned or the crimes committed. On the other hand, y axis is the number of data points for every value of x axis.
 Standard deviation can be defined as the mean of the mean. This helps the analyst to find the story behind the data. This helps to understand the concept of normal distribution. A normal distribution of the certain data means that the most of the in the set of data which is close to the average, on the other hand, relatively few example tend to one extreme (Lee et al.  2008).
               

Coefficient of Variation

The correlation coefficient of the two variables in the data sample can be defined as the covariance divided by the product of the individual’s standard of the variation. This can be known as normalized measurement of how they are linearly related. A correlation coefficient is one of the statistical measures of the certain degree of which change to the value of one variable can predict the change to the other variable (Lazaridis, 2005). The negatively correlated value defines that when the value of one variable increase then the value of other variable decrease. The value of r can be defined as the liner correlation coefficient that helps to determine the strength and the direction of the liner relationship between the different variables. The linear correlation can be defined as the Pearson product moment correlation coefficient (Math.mit.edu, 2014). The effective value of r can be -1, +1 or 0 which is used for positive liner correlation and negative liner correlation respectively.
Positive correlation
Positive correlation can be representing by the value of +1. The value of the positive 1 can indicates the perfect positive fit. This value also indicates the relationship between x and y variable. In this case, when the value of x increases then the value of y also increases (Siddiqui and Siddiqui, 2006).
Negative correlation
Negative correlation indicates that the value of -1. The value of negative 1 represent the perfect negative fit. The negative value indicates the negative relationship such that when the value of x increase then the value of y decrease (Madura, 2011).
No correlation
No correlation indicates the weak linear correlation. In this case the value of r is close to 0. A value of zero means that there is no relation between two variables. That indicates that if the value of x increase then the value of y may not change (Math.umn.edu, 2014).

Calculation

Mean
Mean
Median
Mode
Standard deviation
Price
29
124
69
79.64251

Price and gender
SUMMARY OUTPUT
Regression Statistics
Multiple R
0.138716
R Square
0.019242
Adjusted R Square
0.008582
Standard Error
78.53473
Observations
94
ANOVA

Df
SS
MS
F
Significance F
Regression
1
11132.73
11132.73
1.805004
0.182413192
Residual
92
567428.7
6167.703
Total
93
578561.4




Coefficients
Standard Error
t Stat
P-value
Lower 95%
Upper 95%
Lower 95.0%
Upper 95.0%
Intercept
164.2359
24.37366
6.738255
1.37E-09
115.8277393
212.6441
115.8277
212.6441
1
-23.7965
17.71229
-1.3435
0.182413
-58.97466951
11.3816
-58.9747
11.3816

The residual output of above calculation will be given below         
RESIDUAL OUTPUT
Observation
Predicted 267
Residuals
1
140.4394
76.56061
2
140.4394
106.5606
3
140.4394
106.5606
4
140.4394
138.5606
5
140.4394
116.5606
6
140.4394
136.5606
7
140.4394
126.5606
8
140.4394
164.5606
9
140.4394
136.5606
10
140.4394
106.5606
11
140.4394
146.5606
12
140.4394
166.5606
13
140.4394
66.56061
14
140.4394
66.56061
15
140.4394
66.56061
16
140.4394
124.5606
17
116.6429
68.35714
18
116.6429
68.35714
19
116.6429
66.35714
20
140.4394
58.56061
21
140.4394
102.5606
22
140.4394
22.56061
23
140.4394
111.5606
24
140.4394
82.56061
25
140.4394
72.56061
26
140.4394
42.56061
27
140.4394
32.56061
28
140.4394
2.560606
29
116.6429
76.35714
30
116.6429
66.35714
31
140.4394
-1.43939
32
140.4394
2.560606
33
140.4394
22.56061
34
116.6429
16.35714
35
116.6429
6.357143
36
140.4394
-7.43939
37
140.4394
-67.4394
38
140.4394
-57.4394
39
140.4394
18.56061
40
140.4394
47.56061
41
116.6429
0.357143
42
116.6429
-5.64286
43
116.6429
60.35714
44
140.4394
-1.43939
45
140.4394
-51.4394
46
116.6429
-19.6429
47
116.6429
-47.6429
48
116.6429
-59.6429
49
116.6429
18.35714
50
116.6429
40.35714
51
116.6429
42.35714
52
116.6429
2.357143
53
140.4394
-101.439
54
140.4394
-21.4394
55
116.6429
-47.6429
56
140.4394
-71.4394
57
116.6429
-87.6429
58
116.6429
-47.6429
59
140.4394
-75.4394
60
140.4394
-36.4394
61
140.4394
-89.4394
62
140.4394
-89.4394
63
140.4394
-97.4394
64
116.6429
-87.6429
65
140.4394
-65.4394
66
140.4394
-71.4394
67
140.4394
-85.4394
68
140.4394
-85.4394
69
140.4394
-85.4394
70
140.4394
-99.4394
71
140.4394
-91.4394
72
140.4394
-89.4394
73
140.4394
-95.4394
74
140.4394
-75.4394
75
140.4394
-75.4394
76
140.4394
-97.4394
77
140.4394
-97.4394
78
116.6429
-51.6429
79
116.6429
-80.6429
80
116.6429
-0.64286
81
116.6429
-42.6429
82
140.4394
-94.4394
83
140.4394
-14.4394
84
140.4394
-74.4394
85
140.4394
-92.4394
86
140.4394
-102.439
87
140.4394
-106.439
88
140.4394
-104.439
89
116.6429
-50.6429
90
116.6429
58.35714
91
116.6429
38.35714
92
140.4394
-28.4394
93
140.4394
45.56061
94
140.4394
-16.4394

Price and type
SUMMARY OUTPUT
Regression Statistics
Multiple R
0.63254
R Square
0.400107
Adjusted R Square
0.393586
Standard Error
61.42111
Observations
94
ANOVA

Df
SS
MS
F
Significance F
Regression
1
231486.5
231486.5
61.3607
7.98903E-12
Residual
92
347074.9
3772.553
Total
93
578561.4




Coefficients
Standard Error
t Stat
P-value
Lower 95%
Upper 95%
Lower 95.0%
Upper 95.0%
Intercept
287.0064
20.61327
13.92338
2.25E-24
246.0666549
327.9461
246.0667
327.9461
1
-99.611
12.71635
-7.83331
7.99E-12
-124.8667935
-74.3553
-124.867
-74.3553


The residual output of above calculation will be given below         
RESIDUAL OUTPUT
Observation
Predicted 267
Residuals
1
187.3953
29.60465
2
187.3953
59.60465
3
187.3953
59.60465
4
187.3953
91.60465
5
187.3953
69.60465
6
187.3953
89.60465
7
187.3953
79.60465
8
187.3953
117.6047
9
187.3953
89.60465
10
187.3953
59.60465
11
187.3953
99.60465
12
187.3953
119.6047
13
187.3953
19.60465
14
187.3953
19.60465
15
187.3953
19.60465
16
187.3953
77.60465
17
187.3953
-2.39535
18
87.78431
97.21569
19
87.78431
95.21569
20
187.3953
11.60465
21
187.3953
55.60465
22
187.3953
-24.3953
23
187.3953
64.60465
24
187.3953
35.60465
25
187.3953
25.60465
26
187.3953
-4.39535
27
187.3953
-14.3953
28
187.3953
-44.3953
29
87.78431
105.2157
30
87.78431
95.21569
31
187.3953
-48.3953
32
187.3953
-44.3953
33
87.78431
75.21569
34
87.78431
45.21569
35
87.78431
35.21569
36
187.3953
-54.3953
37
187.3953
-114.395
38
187.3953
-104.395
39
187.3953
-28.3953
40
187.3953
0.604651
41
187.3953
-70.3953
42
187.3953
-76.3953
43
187.3953
-10.3953
44
87.78431
51.21569
45
87.78431
1.215686
46
87.78431
9.215686
47
87.78431
-18.7843
48
87.78431
-30.7843
49
87.78431
47.21569
50
87.78431
69.21569
51
87.78431
71.21569
52
187.3953
-68.3953
53
87.78431
-48.7843
54
87.78431
31.21569
55
87.78431
-18.7843
56
187.3953
-118.395
57
187.3953
-158.395
58
187.3953
-118.395
59
87.78431
-22.7843
60
87.78431
16.21569
61
87.78431
-36.7843
62
87.78431
-36.7843
63
87.78431
-44.7843
64
87.78431
-58.7843
65
87.78431
-12.7843
66
87.78431
-18.7843
67
87.78431
-32.7843
68
87.78431
-32.7843
69
87.78431
-32.7843
70
87.78431
-46.7843
71
87.78431
-38.7843
72
87.78431
-36.7843
73
87.78431
-42.7843
74
87.78431
-22.7843
75
87.78431
-22.7843
76
87.78431
-44.7843
77
87.78431
-44.7843
78
87.78431
-22.7843
79
87.78431
-51.7843
80
87.78431
28.21569
81
187.3953
-113.395
82
87.78431
-41.7843
83
87.78431
38.21569
84
87.78431
-21.7843
85
87.78431
-39.7843
86
87.78431
-49.7843
87
87.78431
-53.7843
88
87.78431
-51.7843
89
87.78431
-21.7843
90
87.78431
87.21569
91
87.78431
67.21569
92
187.3953
-75.3953
93
187.3953
-1.39535
94
87.78431
36.21569

Price and country
SUMMARY OUTPUT
Regression Statistics
Multiple R
0.058164
R Square
0.003383
Adjusted R Square
-0.00745
Standard Error
79.16714
Observations
94
ANOVA

Df
SS
MS
F
Significance F
Regression
1
1957.318
1957.318
0.3123
0.57763
Residual
92
576604.1
6267.436
Total
93
578561.4




Coefficients
Standard Error
t Stat
P-value
Lower 95%
Upper 95%
Lower 95.0%
Upper 95.0%
Intercept
146.003
24.06721
6.066469
2.87E-08
98.20342
193.8025
98.20342
193.8025
1
-6.25937
11.20069
-0.55884
0.57763
-28.5049
15.98617
-28.5049
15.98617

The residual output of above calculation will be given below         
RESIDUAL OUTPUT
Observation
Predicted 267
Residuals
1
139.7436
77.25639
2
139.7436
107.2564
3
139.7436
107.2564
4
139.7436
139.2564
5
139.7436
117.2564
6
139.7436
137.2564
7
139.7436
127.2564
8
133.4842
171.5158
9
133.4842
143.5158
10
133.4842
113.5158
11
133.4842
153.5158
12
133.4842
173.5158
13
133.4842
73.51576
14
133.4842
73.51576
15
133.4842
73.51576
16
133.4842
131.5158
17
133.4842
51.51576
18
133.4842
51.51576
19
133.4842
49.51576
20
127.2249
71.77513
21
127.2249
115.7751
22
127.2249
35.77513
23
127.2249
124.7751
24
127.2249
95.77513
25
127.2249
85.77513
26
127.2249
55.77513
27
127.2249
45.77513
28
127.2249
15.77513
29
127.2249
65.77513
30
127.2249
55.77513
31
139.7436
-0.74361
32
139.7436
3.256388
33
139.7436
23.25639
34
139.7436
-6.74361
35
139.7436
-16.7436
36
133.4842
-0.48424
37
133.4842
-60.4842
38
133.4842
-50.4842
39
133.4842
25.51576
40
133.4842
54.51576
41
133.4842
-16.4842
42
133.4842
-22.4842
43
133.4842
43.51576
44
133.4842
5.515758
45
133.4842
-44.4842
46
133.4842
-36.4842
47
133.4842
-64.4842
48
133.4842
-76.4842
49
133.4842
1.515758
50
133.4842
23.51576
51
133.4842
25.51576
52
127.2249
-8.22487
53
127.2249
-88.2249
54
127.2249
-8.22487
55
127.2249
-58.2249
56
139.7436
-70.7436
57
139.7436
-110.744
58
139.7436
-70.7436
59
139.7436
-74.7436
60
139.7436
-35.7436
61
139.7436
-88.7436
62
139.7436
-88.7436
63
139.7436
-96.7436
64
139.7436
-110.744
65
133.4842
-58.4842
66
133.4842
-64.4842
67
133.4842
-78.4842
68
133.4842
-78.4842
69
133.4842
-78.4842
70
133.4842
-92.4842
71
133.4842
-84.4842
72
133.4842
-82.4842
73
133.4842
-88.4842
74
133.4842
-68.4842
75
133.4842
-68.4842
76
133.4842
-90.4842
77
133.4842
-90.4842
78
133.4842
-68.4842
79
133.4842
-97.4842
80
133.4842
-17.4842
81
127.2249
-53.2249
82
127.2249
-81.2249
83
127.2249
-1.22487
84
127.2249
-61.2249
85
127.2249
-79.2249
86
127.2249
-89.2249
87
127.2249
-93.2249
88
127.2249
-91.2249
89
127.2249
-61.2249
90
127.2249
47.77513
91
127.2249
27.77513
92
139.7436
-27.7436
93
139.7436
46.25639
94
139.7436
-15.7436

Price and intensity
SUMMARY OUTPUT
Regression Statistics
Multiple R
0.881551
R Square
0.777131
Adjusted R Square
0.774709
Standard Error
37.43736
Observations
94
ANOVA

Df
SS
MS
F
Significance F
Regression
1
449618.2
449618.2
320.7993
9.61E-32
Residual
92
128943.2
1401.556
Total
93
578561.4




Coefficients
Standard Error
t Stat
P-value
Lower 95%
Upper 95%
Lower 95.0%
Upper 95.0%
Intercept
300.2355
10.08592
29.76777
5.2E-49
280.204
320.267
280.204
320.267
1
-82.5639
4.609707
-17.9109
9.61E-32
-91.7191
-73.4086
-91.7191
-73.4086

The residual output of above calculation will be given below         
RESIDUAL OUTPUT
Observation
Predicted 267
Residuals
1
217.6716
-0.67161
2
217.6716
29.32839
3
217.6716
29.32839
4
217.6716
61.32839
5
217.6716
39.32839
6
217.6716
59.32839
7
217.6716
49.32839
8
217.6716
87.32839
9
217.6716
59.32839
10
217.6716
29.32839
11
217.6716
69.32839
12
217.6716
89.32839
13
217.6716
-10.6716
14
217.6716
-10.6716
15
217.6716
-10.6716
16
217.6716
47.32839
17
217.6716
-32.6716
18
217.6716
-32.6716
19
217.6716
-34.6716
20
217.6716
-18.6716
21
217.6716
25.32839
22
217.6716
-54.6716
23
217.6716
34.32839
24
217.6716
5.328387
25
217.6716
-4.67161
26
217.6716
-34.6716
27
217.6716
-44.6716
28
217.6716
-74.6716
29
217.6716
-24.6716
30
217.6716
-34.6716
31
135.1077
3.892258
32
135.1077
7.892258
33
135.1077
27.89226
34
135.1077
-2.10774
35
135.1077
-12.1077
36
135.1077
-2.10774
37
135.1077
-62.1077
38
135.1077
-52.1077
39
135.1077
23.89226
40
135.1077
52.89226
41
135.1077
-18.1077
42
135.1077
-24.1077
43
135.1077
41.89226
44
135.1077
3.892258
45
135.1077
-46.1077
46
135.1077
-38.1077
47
135.1077
-66.1077
48
135.1077
-78.1077
49
135.1077
-0.10774
50
135.1077
21.89226
51
135.1077
23.89226
52
135.1077
-16.1077
53
135.1077
-96.1077
54
135.1077
-16.1077
55
135.1077
-66.1077
56
52.54387
16.45613
57
52.54387
-23.5439
58
52.54387
16.45613
59
52.54387
12.45613
60
52.54387
51.45613
61
52.54387
-1.54387
62
52.54387
-1.54387
63
52.54387
-9.54387
64
52.54387
-23.5439
65
52.54387
22.45613
66
52.54387
16.45613
67
52.54387
2.456129
68
52.54387
2.456129
69
52.54387
2.456129
70
52.54387
-11.5439
71
52.54387
-3.54387
72
52.54387
-1.54387
73
52.54387
-7.54387
74
52.54387
12.45613
75
52.54387
12.45613
76
52.54387
-9.54387
77
52.54387
-9.54387
78
52.54387
12.45613
79
52.54387
-16.5439
80
52.54387
63.45613
81
52.54387
21.45613
82
52.54387
-6.54387
83
52.54387
73.45613
84
52.54387
13.45613
85
52.54387
-4.54387
86
52.54387
-14.5439
87
52.54387
-18.5439
88
52.54387
-16.5439
89
52.54387
13.45613
90
217.6716
-42.6716
91
217.6716
-62.6716
92
135.1077
-23.1077
93
135.1077
50.89226
94
135.1077
-11.1077

Conclusion

From the calculation it is observed that the value of mean will be 29 and the value of the median will be 124. On the other hand, it is observed that the value of the mode will be 69 and the value of the standard deviation will be 79.64251.
Price and gender
From the above calculation it is observe that the value of R square is .0192 which is not good fit. 1 per cent of the variation in price is explained by the gender. Here the significance F is .1824. Here, the regression line is in negative slope.
Price and type
From the calculation it is observed that, the value of R square will be .400. It indicates that there is good fit between price of the products and products type. Here, the value of significance F is 7.989.
Price and country
From the calculation it is observed that the value of R square will be .0033 which indicates there is no good fit. Here, the value of significance F will be .57763. The price of the product may not dependent by the area where it is produced.  
Price and intensity

From the above calculation, it is observed that the value of the R square will be .777 which is the good fit. It indicates 77 per cent of variation in price is explained by the variables of intensity. Here, the significance F is 9.61.